answer:Jake has 12 fewer peaches than Steven. Since Steven has 19 peaches, we subtract 12 from 19 to find out how many peaches Jake has: 19 - 12 = 7 peaches So, Jake has boxed{7} peaches.

answer:Solve: mx > 6x + 3, By rearranging, we get (m-6)x > 3, Since m < 5, Then m-6 < 0, Therefore, x < frac{3}{m-6}. Hence, the answer is: x < frac{3}{m-6}. So, the final answer is boxed{x < frac{3}{m-6}}.

answer:Let's denote the distance between town R and town B as ( d_{RB} ) and the distance between town B and town C as ( d_{BC} ). Tom drives from R to B at 60 mph, and from B to C at 20 mph. The average speed for the whole journey is 36 mph. The time it takes to travel from R to B is ( t_{RB} = frac{d_{RB}}{60} ) hours, and the time it takes to travel from B to C is ( t_{BC} = frac{d_{BC}}{20} ) hours. The total distance traveled is ( d_{RB} + d_{BC} ), and the total time is ( t_{RB} + t_{BC} ). The average speed is the total distance divided by the total time, so: [ 36 = frac{d_{RB} + d_{BC}}{t_{RB} + t_{BC}} ] Substituting the expressions for ( t_{RB} ) and ( t_{BC} ) we get: [ 36 = frac{d_{RB} + d_{BC}}{frac{d_{RB}}{60} + frac{d_{BC}}{20}} ] Multiplying both sides by ( frac{d_{RB}}{60} + frac{d_{BC}}{20} ) to clear the denominator, we get: [ 36 left( frac{d_{RB}}{60} + frac{d_{BC}}{20} right) = d_{RB} + d_{BC} ] Expanding the left side, we get: [ frac{36d_{RB}}{60} + frac{36d_{BC}}{20} = d_{RB} + d_{BC} ] Simplifying the fractions, we get: [ frac{3d_{RB}}{5} + frac{9d_{BC}}{5} = d_{RB} + d_{BC} ] Multiplying through by 5 to clear the denominators, we get: [ 3d_{RB} + 9d_{BC} = 5d_{RB} + 5d_{BC} ] Rearranging the terms, we get: [ 5d_{RB} - 3d_{RB} = 9d_{BC} - 5d_{BC} ] [ 2d_{RB} = 4d_{BC} ] Dividing both sides by ( 2d_{BC} ), we get: [ frac{d_{RB}}{d_{BC}} = frac{4}{2} ] [ frac{d_{RB}}{d_{BC}} = 2 ] So the ratio of the distance between R and B to the distance between B and C is boxed{2:1} .

answer:First, let's calculate the total income from each type of repair and the total cost of parts for each, before any discounts: 1) Fixing bike tires: Income: 20 x 300 = 6000 Cost of parts: 5 x 300 = 1500 2) Fixing bike chains: Income: 75 x 50 = 3750 Cost of parts: 25 x 50 = 1250 3) Overhauling entire bikes: Income: 300 x 8 = 2400 Cost of parts: 50 x 8 = 400 Now, let's add the income from retail sales: Retail sales income: 2000 Total income from all sources: 6000 (tires) + 3750 (chains) + 2400 (bikes) + 2000 (retail) = 15150 Total cost of parts before discount: 1500 (tires) + 1250 (chains) + 400 (bikes) = 3150 Since Jim spends more than 2500 on parts, he gets a 10% discount. Let's calculate the discount amount and the final cost of parts: Discount: 10% of 3150 = 0.10 x 3150 = 315 Final cost of parts after discount: 3150 - 315 = 2835 Now, let's calculate the profit from repairs and retail before taxes: Profit from repairs: 15150 (total income) - 2835 (cost of parts) = 12315 Profit from retail: 2000 (retail sales) - 1200 (cost of retail goods) = 800 Total profit before taxes: 12315 (repairs) + 800 (retail) = 13115 Now, let's calculate the taxes: Taxes: 6% of 15150 (total income from repairs and retail) = 0.06 x 15150 = 909 Profit after taxes: 13115 (total profit before taxes) - 909 (taxes) = 12206 Finally, let's subtract the fixed expenses: Profit after all expenses: 12206 (profit after taxes) - 4000 (fixed expenses) = 8206 Jim's bike shop made a profit of boxed{8206} in the first month.